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7x^2+4x-195=0
a = 7; b = 4; c = -195;
Δ = b2-4ac
Δ = 42-4·7·(-195)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-74}{2*7}=\frac{-78}{14} =-5+4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+74}{2*7}=\frac{70}{14} =5 $
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